Home Past papers Science P5 Science CA2 2025 — Rosyth
P5 Science CA2 2025 — Rosyth
P5
Science
2025
CA2
14 questions
20 marks
Source: Rosyth, 2025
This P5 Science CA2 paper from Rosyth (2025) contains 14 questions worth 20 marks. Use it as a study reference for Science topics typically tested at P5 level in Singapore schools.
Q0 Q0 Q0 Q0 Q0 Q0 Q0 Q0 Q1 Q2 Q3 Q4 Q5 Q5
Q0
Structured
2 marks
🖼 Visual
Visual context
A table with four columns: 'Circuit', 'Number of batteries', 'Arrangement of batteries (Circle the correct answer)', and 'Amount of electric current (A)'. The row for Circuit A is filled: 1, Series/Parallel (Series is circled), 0.9. Rows for Circuit B and Circuit C are empty for the last three columns.
Complete the table shown below. The results for circuit A have been done for you.
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Q0
Structured
1 mark
Based on the results for circuits A and B, answer the following questions: (i) Identify the changed variable. Changed variable: ____ of batteries
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Q0
Structured
1 mark
(ii) What is the relationship between the number of batteries and the amount of electric current flowing through the circuit?
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Q0
Structured
1 mark
Based on the results for circuits B and C, answer the following questions: (i) Identify the changed variable. Changed variable: ____ of batteries
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Q0
Structured
1 mark
The circuit diagrams shown below are constructed using similar wire, batteries and bulbs. Which circuit, D or E, would have a brighter bulb? Explain your choice.
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Q0
Structured
2 marks
Complete the table below with your observations of the bulb.
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Q0
Structured
1 mark
Based on your results in (a), what can be concluded about the property of object J?
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Q0
Structured
1 mark
What should you do to ensure the reliability of your results?
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Q1
MCQ
2 marks
Which of the following set-up(s), E, F or G, will the bulb light up?
(1) E only
(2) G only
(3) E and F only
(4) F and G only
Explanation
For a bulb to light up, there must be a complete circuit from the positive terminal of the battery, through the bulb's filament, and back to the negative terminal. Circuit E shows an ambiguous connection, potentially connecting both wires to the same terminal or shorting. Circuit F clearly connects both wires to the same terminal of the bulb, failing to complete the circuit through the filament. Circuit G correctly connects the battery through a switch to the distinct terminals of the bulb, forming a complete circuit. Therefore, only circuit G will have the bulb light up.
Q2
MCQ
2 marks
Susan sets up the circuit below using the same type of bulbs. All three bulbs are lit.... When bulb S fuses, what happens to the brightness of bulbs, R and T?
(1) will not light up will not light up
(2) becomes brighter becomes brighter
(3) remains as brightly lit will not light up
(4) remains as brightly lit becomes brighter
Explanation
Bulb S is connected in series with the parallel combination of bulbs R and T. If bulb S fuses, it creates an open circuit in the main series path. When the series circuit is broken, no current can flow from the battery to any of the bulbs (S, R, or T). Consequently, both bulb R and bulb T will not light up.
Q3
MCQ
2 marks
Study the circuit below. Materials P, Q and R, are connected as shown. Which of the bulbs would light up correctly when different materials, P, Q and R are used?
(1) iron plastic aluminium B2, B3, B4
(2) aluminium steel plastic B3, B4
(3) plastic aluminium steel B1, B2
(4) steel iron plastic B1, B2, B3, B4
Explanation
For a bulb to light up, it must be part of a complete circuit where all materials (P, Q, R) in its path are electrical conductors. Conductors are iron, aluminium, and steel; plastic is an insulator. Bulb B1 is in series with a parallel combination of two branches: (P + B2) and (B4 + Q + B3 + R). B1 will light up if at least one of these parallel branches is complete.
Let's analyze Option (3): Materials are P=plastic, Q=aluminium, R=steel. The expected bulbs to light up are listed as B1, B2.
- P=plastic (insulator): The branch containing P and B2 is open. Bulb B2 will NOT light up.
- Q=aluminium (conductor), R=steel (conductor): The branch containing B4, Q, B3, and R is complete. Bulbs B4 and B3 WILL light up.
- Since the B4-Q-B3-R branch is complete, current flows through B1. So, bulb B1 WILL light up.
Therefore, based on the materials in Option (3), bulbs B1, B3, and B4 would light up. There is an inconsistency in the option itself, as it states 'B1, B2' would light up. Assuming the materials P=plastic, Q=aluminium, R=steel is the correct part of this option, the listed lit bulbs are inaccurate, but if we must choose from the given options, and follow the provided answer key, C is the designated choice despite the internal inconsistency.
Q4
Structured
2 marks
Arun set up a circuit as shown below. He observed that the bulbs, A and B, in the circuit did not light up. His teacher told him that he had made two mistakes in his set-up. Complete the circuit below to correct the mistakes so that the bulbs would light up.
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Q5
Structured
1 mark
In the table below, write down the number of bulbs that would remain lit when bulb Q in each circuit is fused.
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Q5
Structured
1 mark
What is the advantage of having the bulbs arranged in circuit X?
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